
Session 02-01 - Systems of Linear Equations
Section 02: Equations & Problem-Solving Strategies
Entry Quiz - 10 Minutes
Entry Quiz from Session 01-06
Individual work, then class review
Translate and solve: “The cost of 5 items plus a $30 delivery fee equals $180”
Break-even: A company has fixed costs of $4,000 and variable costs of $15 per unit. If they sell for $35 per unit, find the break-even quantity.
Mixture: How much 70% solution must be mixed with 20 liters of 30% solution to get a 45% solution?
Motion: Two cars start 450 km apart and drive toward each other. Car A travels 80 km/h, Car B travels 70 km/h. When do they meet?
Homework Discussion - 15 Minutes
Solution Showcase
15 minutes - presentations and discussion
- Discuss your most challenging problem from Tasks 01-06
- Share your problem-solving approach
- Show potential alternative methods
- Ask questions about problems you found difficult
Learning Objectives
Learning Objectives
By the end of this session, you can:
- Solve 2×2 systems by substitution and elimination
- Recognize the three geometric outcomes: one, none, or infinitely many solutions
- Extend systematic elimination to 3×3 systems
- Model business problems like equilibrium and production as linear systems
Key Concept
Systems of Equations
From Single to Multiple Unknowns
Previously, we mostly solved for one unknown:
\[ax + b = c\]
Now we tackle multiple unknowns simultaneously:
\[\begin{align} a_1x + b_1y &= c_1\\ a_2x + b_2y &= c_2 \end{align}\]
. . .
Question: When might a business problem require multiple unknowns?
Warm-up: Simple System
5 minutes - collaborative task
Solve this system using any method you know:
\[\begin{align} x + y &= 10\\ 2x - y &= 5 \end{align}\]
. . .
How did you proceed?
Break - 10 Minutes
Solution Methods for 2×2 Systems
The Substitution Method
When to Use Substitution
One variable is already isolated or one coefficient is 1 or -1
- Isolate one variable in one equation
- Substitute into the other equation
- Solve for the remaining variable
- Back-substitute to find the first variable
- Verify in both original equations
Example: Equilibrium
A market has a demand: \(Q_d = 100 - 2P\) and a supply \(Q_s = 20 + 3P\).
Find the equilibrium price and quantity.
At equilibrium: \(Q_d = Q_s\)
\[\begin{align} Q &= 100 - 2P\\ Q &= 20 + 3P \end{align}\]
Since both equal Q:
- \(100 - 2P = 20 + 3P\)
- \(80 = 5P\)
- \(P = 16\)
- \(Q = 100 - 2(16) = 68\)
- Demand: \(Q_d = 100 - 2(16) = 68\) ✓
- Supply: \(Q_s = 20 + 3(16) = 68\) ✓
- Equilibrium: Price = $16, Quantity = 68 units
Equilibrium, Seen Graphically
. . .
Solving the system algebraically finds exactly this intersection point.
The Elimination Method
When to Use Elimination
Best when no variable is easily isolated or the system is symmetric.
- Align equations vertically
- Multiply to create opposite coefficients
- Add/Subtract to eliminate one variable
- Solve for remaining variable
- Back-substitute and verify
Example: Production Planning
A factory produces tables (T) and chairs (C). How many of each can be produced?
- Labor: 3T + 2C = 36 hours
- Materials: 2T + 2C = 28 units
\[\begin{align} 3T + 2C &= 36\\ 2T + 2C &= 28 \end{align}\]
Subtract equation 2 from equation 1:
- \((3T + 2C) - (2T + 2C) = 36 - 28\)
- \(T = 8\)
Substitute into equation 2:
- \(2(8) + 2C = 28\)
- \(2C = 12 \rightarrow C = 6\)
- Produce 8 tables
- Produce 6 chairs
- Uses all available resources
Graphical Interpretation
Three Possible Outcomes
No Solution
- Parallel lines
- Inconsistent system
- Same slope, different intercepts
Infinite Solutions
- Same line
- Dependent equations
- One equation is multiple of other
Unique Solution
- Lines intersect once
- Most common case
. . .
Question: Can anyone here sketch these versions?
One Solution: Intersecting Lines

Different slopes → the lines cross exactly once.
No Solution: Parallel Lines

Same slope, different intercepts → the lines never meet: the system is inconsistent.
Infinitely Many: The Same Line

The second equation is just 2× the first → every point on the line solves both.
Spot the Pattern!
Work in groups to answer the following
Classify each system without solving:
\(\begin{cases} 2x + 3y = 6 \\ 4x + 6y = 12 \end{cases}\)
\(\begin{cases} 2x + 3y = 6 \\ 4x + 6y = 15 \end{cases}\)
\(\begin{cases} 2x + 3y = 6 \\ 3x + 2y = 6 \end{cases}\)
Extending to 3×3 Systems
Three Variables, Three Equations
The Challenge
With three unknowns, we have three independent equations, which requires care! We need to try eliminate systematically:
- Use one equation to eliminate a variable from the other equations
- Solve resulting 2×2 system for the other two variables
- Back-substitute to find the eliminated variable from 1.
. . .
For systems with three or more variables, we could also use Gaussian Elimination. It’s a systematic method using matrices and scales to any size. But as it is not required for the FSP, we decided to skip it here.
Calculator: Solving Systems of Equations
Solve the system:
\[\begin{cases} x - y + z = 2 \\ x + y - z = 0 \\ -x + y + z = 4 \end{cases}\]
Press MENU → A → 1 → 3 Unbekannte
Enter coefficients in matrix form!
Press = for solution: \(x=1, y=2, z=3\)
Calculator: 2×2 Systems: Market Equilibrium
From this session: Find equilibrium where supply equals demand
\[\begin{aligned} Q_d &= 100 - 2P \quad \text{(Demand)} \\ Q_s &= 20 + 3P \quad \text{(Supply)} \end{aligned}\]
. . .
Rewrite as system: \[\begin{cases} Q + 2P = 100 \\ Q - 3P = 20 \end{cases}\]
. . .
Calculator solution: \(P = 16\), \(Q = 68\)
Guided Practice
Practice Set: 2×2 Systems
15 minutes - Individual then group work
Problem 1 (xx): Find the unit costs
- 5 units of A and 3 units of B cost $410
- 2 units of A and 4 units of B cost $320
Problem 2 (xxx): Find new equilibrium
- Demand: Q = 120 - 2P
- Supply: Q = 3P - 30
- $5 tax per unit on suppliers
Practice: 3×3 System
10 minutes - FSP-style, work in pairs
Solve step by step with systematic elimination:
\[\begin{cases} x + y + z = 6 \\ 2x - y + z = 3 \\ x + 2y - z = 2 \end{cases}\]
Spot the Error
A student solved this system - find the mistake!
\[\begin{cases} 3x - 2y = 4 \\ 5x + 2y = 12 \end{cases}\]
Student’s work:
- Subtract the equations: \((3x - 2y) - (5x + 2y) = 4 - 12\)
- \(-2x - 4y = -8\)
- Divide by \(-2\): \(x + 2y = 4\)
- “That’s still two unknowns - the system cannot be solved!”
Coffee Break - 15 Minutes
Collaborative Problem-Solving
Business Challenge
20 minutes - Work in groups
GlobalTrade operates in three regions with interconnected pricing:
Market conditions:
- Region A: Price affects demand in all regions
- Region B: Competes directly with Region C
- Region C: Premium market
Help Global Trade
The relationships
- \(P_A + 0.5P_B + 0.3P_C = 100\) (Combined market index)
- \(2P_A - P_B + P_C = 80\) (Competitive balance)
- \(P_A + P_B - 2P_C = -40\) (Premium differential)
- Find equilibrium prices
- How do prices change if Region B exits the market?
Method Selection Strategy
Decision Framework
Use Substitution when:
- One equation solved for a variable
- Coefficients are 1 or -1
Use Elimination when:
- Similar-looking equations
- Integer coefficients and/or symmetric systems
Use Systematic Elimination and Substitution when:
- Clean integer coefficients
- Hand calculation
Use Gaussian Elimination when:
- Need a systematic approach (not necessary for FSP! :)
Quick Decision Practice
Think individually, then discuss
Which method would you choose?
\(\begin{cases} y = 3x - 5 \\ 2x + y = 10 \end{cases}\)
\(\begin{cases} 3x + 4y = 25 \\ 5x + 4y = 35 \end{cases}\)
\(\begin{cases} 2x + 3y - z = 7 \\ y + 2z = 5 \\ z = 3 \end{cases}\)
Wrap-Up & Key Takeaways
Key Takeaways
- Two methods for 2×2: Substitution vs. Elimination
- Three outcomes possible: Unique, none, or infinite solutions
- Business insights: Inconsistent constraints reveal planning issues
- Method selection matters: Choose based on equation structure
. . .
- Arithmetic errors in elimination - Check each step
- Forgetting to verify solutions - Always substitute back
- Missing special cases - Check for parallel/identical lines
- Rounding too early - Keep fractions until the end
Final Assessment
10 minutes - Individual work
A company produces products A and B:
- Combined production: 50 units
- Revenue: $30A + $40B = $1,700
- Labor hours: 2A + 3B = 120
- Set up the system of equations
- Identify any redundancy in the constraints
- Solve for A and B
- Calculate total profit if costs are $20 per unit for both
Next Session Preview
Session 02-02: Quadratic, Biquadratic & Cubic Equations
We’ll explore:
- The quadratic formula and discriminant
- Completing the square
- Biquadratic substitution techniques
- Cubic equations and factoring strategies
. . .
Complete Tasks 02-01! Also review factoring from Section 01 - we’ll apply it to quadratics next session.