Tasks 01-02 - Mathematical Foundations
Language, Sets, and Number Systems
Problem 1: Set Operations
Let \(U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}\) be the universal set.
Let \(A = \{2, 3, 5, 7\}\) and \(B = \{1, 2, 3, 4, 5\}\).
Find:
- \(A \cup B\)
- \(A \cap B\)
- \(A \setminus B\)
- \(B \setminus A\)
- \(A \cup B = \{1, 2, 3, 4, 5, 7\}\)
- \(A \cap B = \{2, 3, 5\}\)
- \(A \setminus B = \{7\}\)
- \(B \setminus A = \{1, 4\}\)
Problem 2: Properties of Operations
Determine if each statement is true or false. Provide a counterexample if false.
- Subtraction is associative: \((a - b) - c = a - (b - c)\)
- Division is commutative: \(\frac{a}{b} = \frac{b}{a}\)
- Multiplication distributes over subtraction: \(a(b - c) = ab - ac\)
- Addition distributes over multiplication: \(a + (b \times c) = (a + b) \times (a + c)\)
- False: \((5 - 3) - 2 = 0\) but \(5 - (3 - 2) = 4\)
- False: \(\frac{6}{2} = 3\) but \(\frac{2}{6} = \frac{1}{3}\)
- True: This is the distributive property extended to subtraction
- False: \(2 + (3 \times 4) = 14\) but \((2 + 3) \times (2 + 4) = 30\)
Problem 3: Logical Statements
Consider: “If a product is on sale, then its price is reduced by at least 20%”
- Write this using logical notation (define your propositions)
- Is the converse necessarily true?
Let \(p\): “product is on sale”, \(q\): “price reduced by at least 20%”
- \(p \Rightarrow q\)
- Converse (\(q \Rightarrow p\)) is not necessarily true - items can have 20% reduction without being “on sale”
Problem 4: Business Application - Customer Analysis
A company surveys 200 customers about their service preferences:
- 120 use Service A
- 85 use Service B
- 60 use Service C
- 40 use both A and B
- 25 use both B and C
- 35 use both A and C
- 15 use all three services
Calculate:
- How many use exactly one service?
- How many use at least two services?
- How many use none of the services?
Step 1 - Set up the Venn diagram
- Center (all three): 15
- A and B only: 40 - 15 = 25
- B and C only: 25 - 15 = 10
- A and C only: 35 - 15 = 20
- A only: 120 - 25 - 15 - 20 = 60
- B only: 85 - 25 - 15 - 10 = 35
- C only: 60 - 20 - 15 - 10 = 15
Step 2 - Answer the questions
- Exactly one service: 60 + 35 + 15 = 110
- At least two services: 25 + 10 + 20 + 15 = 70
- None: 200 - (60 + 35 + 15 + 25 + 10 + 20 + 15) = 200 - 180 = 20
Problem 5: Interest Rate Calculation
A bank account grows from €5,000 to €5,500 in one year.
- What is the percentage increase?
- If this rate continues, what will be the balance after 3 years?
- Express the growth using set notation (hint: think of the set of all possible balances)
- Percentage increase: \(\frac{5500 - 5000}{5000} \times 100\% = 10\%\)
- After 3 years: \(5000 \times (1.10)^3 = 5000 \times 1.331 = €6,655\)
- Set notation: Let \(B_n = \{b \in \mathbb{R} : b = 5000 \times (1.10)^n, n \in \mathbb{N}_0\}\) This represents all possible balances after n years.
Problem 6: Number Classification and Conversions
For each of the following numbers, classify them by listing ALL applicable number systems (\(\mathbb{N}\), \(\mathbb{Z}\), \(\mathbb{Q}\), \(\mathbb{R}\)) and show your work for conversions where needed:
- \(0.\overline{27}\) (repeating decimal)
- \(\sqrt{16}\)
- \(\frac{-15}{3}\)
- \(0.101001000100001...\) (non-repeating, non-terminating)
- \(0.\overline{27}\): Let \(x = 0.272727...\)
- \(100x = 27.272727...\)
- \(100x - x = 27\), so \(99x = 27\)
- Thus \(x = \frac{27}{99} = \frac{3}{11}\)
- Classification: \(\mathbb{Q}, \mathbb{R}\)
- \(\sqrt{16} = 4\)
- Classification: \(\mathbb{N}, \mathbb{Z}, \mathbb{Q}, \mathbb{R}\)
- \(\frac{-15}{3} = -5\)
- Classification: \(\mathbb{Z}, \mathbb{Q}, \mathbb{R}\)
- \(0.101001000100001...\) (pattern but non-repeating)
- Classification: \(\mathbb{R}\) only (irrational)