Course Cheatsheet
Section 03: Functions as Business Models
What is a Function?
A function is a rule that assigns to each input exactly one output
- Mathematical Definition: For every input \(x\), there is exactly one output \(f(x)\)
- Business Perspective: A model showing cause and effect relationships
- Key Principle: Each input must have exactly one output (no ambiguity)
Function Notation
| Traditional Equation | Function Notation | Meaning |
|---|---|---|
| \(y = 2x + 5\) | \(f(x) = 2x + 5\) | Function \(f\) maps input \(x\) to output \(2x + 5\) |
| \(y = x^2 - 3\) | \(g(x) = x^2 - 3\) | Function \(g\) maps input \(x\) to output \(x^2 - 3\) |
| \(y = \frac{100}{x}\) | \(h(x) = \frac{100}{x}\) | Function \(h\) maps input \(x\) to output \(\frac{100}{x}\) |
Function Evaluation:
- \(f(3)\) means “substitute \(x = 3\) into function \(f\)”
- If \(f(x) = 2x + 5\), then \(f(3) = 2(3) + 5 = 11\)
- If \(g(x) = x^2 - 3\), then \(g(-2) = (-2)^2 - 3 = 1\)
Domain and Range
Domain: All Possible Input Values
Mathematical Restrictions:
| Function Type | Restriction | Domain Rule |
|---|---|---|
| Rational: \(f(x) = \frac{1}{x-a}\) | Denominator ≠ 0 | \(x \neq a\) |
| Square Root: \(f(x) = \sqrt{x-a}\) | Argument ≥ 0 | \(x \geq a\) |
| Logarithm: \(f(x) = \log(x-a)\) | Argument > 0 | \(x > a\) |
| Polynomial: \(f(x) = ax^n + ...\) | No restrictions | All real numbers |
Business Restrictions:
- Quantities cannot be negative: \(x \geq 0\)
- Production capacity limits: \(0 \leq x \leq \text{max capacity}\)
- Time constraints: \(0 \leq t \leq 24\) hours per day
Range: All Possible Output Values
Common Patterns:
| Function Type | Range | Example |
|---|---|---|
| Linear: \(f(x) = ax + b\) | All real numbers | \((-\infty, \infty)\) |
| Quadratic: \(f(x) = x^2 + c\) | \([c, \infty)\) | \(f(x) = x^2 + 2\) has range \([2, \infty)\) |
| Square Root: \(f(x) = \sqrt{x}\) | \([0, \infty)\) | Non-negative outputs |
| Rational: \(f(x) = \frac{1}{x}\) | All except 0 | \((-\infty, 0) \cup (0, \infty)\) |
Four Ways to Represent Functions
1. Verbal Description
“Base cost of 100€ plus 3€ for each additional unit”
2. Algebraic Formula
\(C(x) = 100 + 3x\)
3. Numerical Table
| \(x\) | \(C(x)\) |
|---|---|
| 0 | 100 |
| 10 | 130 |
| 20 | 160 |
4. Graphical Plot
Visual representation showing the relationship between input and output
The Vertical Line Test
Rule: A graph represents a function if and only if every vertical line intersects it at most once.
Examples:
- Pass: Lines, parabolas opening up/down, exponential curves
- Fail: Circles, sideways parabolas, vertical lines
Why Important: Ensures each input has exactly one output (function definition)
Function Evaluation Strategies
Direct Substitution
If \(f(x) = 3x^2 - 5x + 2\), find \(f(4)\): - \(f(4) = 3(4)^2 - 5(4) + 2 = 3(16) - 20 + 2 = 48 - 20 + 2 = 30\)
Piecewise Functions
When function has different rules for different input ranges:
\[f(x) = \begin{cases} 2x + 1 & \text{if } x < 0 \\ x^2 & \text{if } x \geq 0 \end{cases}\]
- \(f(-3) = 2(-3) + 1 = -5\) (use first rule since \(-3 < 0\))
- \(f(5) = 5^2 = 25\) (use second rule since \(5 \geq 0\))
Key Vocabulary
- Function: Rule assigning exactly one output to each input
- Domain: Set of all possible input values
- Range: Set of all possible output values
- Independent Variable: Input variable (usually \(x\))
- Dependent Variable: Output variable (usually \(y\) or \(f(x)\))
- Function Notation: \(f(x)\) read as “\(f\) of \(x\)”
- Vertical Line Test: Method to determine if graph represents function
- Fixed Costs: Business costs independent of production level
- Variable Costs: Business costs proportional to production level
- Break-Even Point: Where revenue equals cost (profit = 0)
Linear Functions in Detail
Forms of Linear Functions
1. Slope-Intercept Form: \(y = mx + b\)
- m: slope (rate of change/marginal change)
- Positive: increasing function
- Negative: decreasing function
- Zero: horizontal line
- b: y-intercept (starting value/base value)
- Value when \(x = 0\)
- Often represents fixed costs or initial values
2. Point-Slope Form: \(y - y_1 = m(x - x_1)\)
- Useful when you know one point \((x_1, y_1)\) and the slope \(m\)
- Best for modeling from observed data
Converting Between Forms:
- From two points \((x_1, y_1)\) and \((x_2, y_2)\):
- Slope: \(m = \frac{y_2 - y_1}{x_2 - x_1}\)
- Use point-slope form, then simplify to slope-intercept
Supply and Demand Functions
Demand Functions
Demand shows how quantity purchased depends on price
- General form: \(Q_d = a - bp\) (decreasing function)
- \(a\): maximum quantity when price = 0
- \(b\): price sensitivity (how much demand drops per unit price increase)
- Alternative form: \(p = c - dQ_d\) (price as function of quantity)
Supply Functions
Supply shows how quantity produced depends on price
- General form: \(Q_s = -c + dp\) (increasing function)
- Often has positive y-intercept
- \(d\): production response to price changes
Market Equilibrium
Equilibrium occurs where supply equals demand: \(Q_d = Q_s\)
- Equilibrium price (\(p^*\)): Market-clearing price
- Equilibrium quantity (\(Q^*\)): Amount actually traded
- Graphically: Intersection point of supply and demand curves
- No shortage or surplus at equilibrium
Example:
- Demand: \(Q_d = 500 - 50p\)
- Supply: \(Q_s = -100 + 100p\)
- Set equal: \(500 - 50p = -100 + 100p\)
- Solve: \(600 = 150p\), so \(p^* = 4\)
- Quantity: \(Q^* = 500 - 50(4) = 300\) units
Cost-Volume-Profit
CVP Framework Components
| Component | Formula | Description |
|---|---|---|
| Fixed Costs (FC) | Constant | Independent of production volume |
| Variable Costs per unit (VC) | Per unit amount | Changes with production |
| Total Costs | \(TC = FC + VC \times Q\) | Sum of fixed and variable costs |
| Revenue | \(R = P \times Q\) | Price × Quantity |
| Profit | \(\Pi = R - TC\) | Revenue minus total costs |
| Contribution Margin | \(CM = P - VC\) | Profit per unit before fixed costs |
CVP Key Calculations
Break-Even Point: \(Q_{BE} = \frac{FC}{CM} = \frac{FC}{P - VC}\)
Target Profit: \(Q_{target} = \frac{FC + \text{Target Profit}}{CM}\)
Margin of Safety: Actual sales - Break-even sales
Linear Modeling from Data
Steps to Create Linear Models
- Identify variables (independent vs dependent)
- Calculate slope between data points
- Use point-slope form to find equation
- Interpret parameters in business context
Example: Sales Forecasting
- Data shows consistent increase of 15 units per month
- Starting at 120 units in month 1
- Model: \(S(m) = 15m + 105\)
Depreciation Models
Linear (Straight-Line) Depreciation
Formula: \(V(t) = V_0 - dt\)
Where:
- \(V(t)\): Value at time \(t\)
- \(V_0\): Initial value
- \(d\): Depreciation rate per period
- Useful life: \(n = \frac{V_0}{d}\) periods
Example: Company Vehicle
- Purchase price: €30,000
- Annual depreciation: €5,000
- Function: \(V(t) = 30,000 - 5,000t\)
- Fully depreciated after 6 years
Quadratic Functions
Standard Form
Formula: \(f(x) = ax^2 + bx + c\)
Key Components: - a: Direction and width - \(a > 0\): Opens upward (U-shape, has minimum) - \(a < 0\): Opens downward (∩-shape, has maximum) - \(|a|\) larger → Narrower parabola - b: Affects position of vertex - c: y-intercept (value when \(x = 0\))
Graph Shape: Parabola (curved, not straight like linear functions)
The Vertex Formula
Key Formula: \(x_v = -\frac{b}{2a}\)
For quadratic function \(f(x) = ax^2 + bx + c\): - Vertex x-coordinate: \(x_v = -\frac{b}{2a}\) - Vertex y-coordinate: \(f(x_v) = f(-\frac{b}{2a})\) - Vertex represents: - Maximum if \(a < 0\) (parabola opens down) - Minimum if \(a > 0\) (parabola opens up) - Axis of symmetry: Vertical line \(x = x_v\)
Vertex Form
Alternative representation: \(f(x) = a(x - h)^2 + k\)
- Vertex: \((h, k)\) - directly visible!
- Direction: \(a\) (same as standard form)
- Advantage: Vertex immediately apparent
- Examples:
- \(f(x) = 2(x - 3)^2 + 5\) → Vertex at \((3, 5)\), minimum
- \(g(x) = -(x + 4)^2 + 10\) → Vertex at \((-4, 10)\), maximum
Completing the Square
Convert from standard form to vertex form
Process:
- Factor out \(a\) from first two terms
- Complete the square inside parentheses: add and subtract \((\frac{b}{2a})^2\)
- Simplify to vertex form \(a(x - h)^2 + k\)
Example: Convert \(f(x) = 2x^2 - 12x + 10\)
- Factor out 2: \(f(x) = 2(x^2 - 6x) + 10\)
- Complete square: Need \((\frac{-6}{2})^2 = 9\)
- Add/subtract 9: \(f(x) = 2(x^2 - 6x + 9 - 9) + 10\)
- Factor perfect square: \(f(x) = 2((x - 3)^2 - 9) + 10\)
- Distribute: \(f(x) = 2(x - 3)^2 - 18 + 10\)
- Final form: \(f(x) = 2(x - 3)^2 - 8\) → Vertex at \((3, -8)\)
Business Optimization with Quadratic Functions
Revenue Optimization (Price-Dependent Demand)
When demand depends on price: \(Q = a - bp\)
- Revenue: \(R(p) = p \times Q = p(a - bp) = ap - bp^2\)
- This creates a quadratic function in price
- Optimal price: \(p^* = -\frac{a}{2(-b)} = \frac{a}{2b}\)
Profit vs Revenue Maximization
Important Distinction:
- Revenue maximization: Ignores costs, focuses on \(R(p) = p \times Q(p)\)
- Profit maximization: Includes costs, \(\Pi(p) = R(p) - C(p)\)
- Different optimal points: Revenue-maximizing price ≠ Profit-maximizing price
Cost Functions (Quadratic)
Some costs increase quadratically with production:
- Formula: \(C(x) = ax^2 + bx + c\)
- Interpretation:
- Fixed costs: \(c\)
- Increasing marginal costs: \(a > 0\)
- Minimum cost production: \(x^* = -\frac{b}{2a}\) (if \(a > 0\))
Profit Functions (Quadratic)
Common form: \(P(x) = -ax^2 + bx + c\) (where \(a > 0\))
- Opens downward: Has maximum profit
- Optimal production: \(x^* = \frac{b}{2a}\)
- Break-even points: Solve \(P(x) = 0\)
Advanced Applications
Area Optimization
Classic problem: Maximize area with constraint
Example: Rectangular storage with 200m fencing - One side against building (no fence needed) - Let \(x\) = width, \(y\) = length along building - Constraint: \(2x + y = 200\) → \(y = 200 - 2x\) - Area: \(A(x) = x \cdot y = x(200 - 2x) = 200x - 2x^2\) - Maximum: \(x^* = \frac{200}{2(2)} = 50m\) - Optimal dimensions: 50m × 100m = 5,000 m²
Projectile Motion in Business
Applications: Product launch campaigns, market penetration
- Formula: \(h(t) = -\frac{g}{2}t^2 + v_0t + h_0\)
- Business analog: \(A(t) = -at^2 + bt + c\) (awareness over time)
- Peak timing: \(t^* = \frac{b}{2a}\)
Example: Marketing Campaign - Awareness: \(A(t) = -2t^2 + 24t\) - Peak at: \(t = \frac{24}{2(2)} = 6\) weeks - Maximum awareness: \(A(6) = 72\) points
Market Analysis Steps
- Identify the quadratic relationship (revenue, profit, cost)
- Find the vertex using \(x = -\frac{b}{2a}\)
- Calculate optimal value by substituting back
- Check constraints (production limits, market capacity)
- Consider break-even points (solve \(f(x) = 0\))
Key Business Insights
- Symmetric behavior: Equal results at equal distances from optimum
- Diminishing returns: Beyond optimal point, additional input reduces output
- Trade-offs: Revenue maximization vs profit maximization
- Constraints matter: Mathematical optimum may not be practically achievable
Function Transformations
Vertical Transformations
Moving graphs up or down
| Transformation | Formula | Effect | Business Example |
|---|---|---|---|
| Vertical Shift Up | \(g(x) = f(x) + k\) (k > 0) | Entire graph moves up | Fixed cost increase |
| Vertical Shift Down | \(g(x) = f(x) - k\) (k > 0) | Entire graph moves down | Government subsidy |
| Vertical Stretch | \(g(x) = a \cdot f(x)\) (a > 1) | Graph becomes taller | Price increase across all products |
| Vertical Compression | \(g(x) = a \cdot f(x)\) (0 < a < 1) | Graph becomes shorter | Discount pricing |
| Reflection over x-axis | \(g(x) = -f(x)\) | Graph flips upside down | Revenue becomes loss |
Business Applications:
- Fixed Cost Changes: \(C_{new}(x) = C(x) + k\) (rent increase of k)
- Percentage Markups: \(R_{new}(x) = 1.2 \cdot R(x)\) (20% price increase)
- Tax Effects: \(P_{net}(x) = 0.8 \cdot P(x)\) (20% tax rate)
Horizontal Transformations
Moving graphs left or right
| Transformation | Formula | Effect | Business Example |
|---|---|---|---|
| Horizontal Shift Right | \(g(x) = f(x - h)\) (h > 0) | Graph moves right | Market entry delay |
| Horizontal Shift Left | \(g(x) = f(x + h)\) (h > 0) | Graph moves left | Early product launch |
| Horizontal Stretch | \(g(x) = f(x/b)\) (b > 1) | Graph becomes wider | Extended product lifecycle |
| Horizontal Compression | \(g(x) = f(bx)\) (b > 1) | Graph becomes narrower | Accelerated lifecycle |
| Reflection over y-axis | \(g(x) = f(-x)\) | Graph flips left-right | Reverse time analysis |
Key Point: Horizontal transformations are counterintuitive!
- \(f(x - 3)\) shifts RIGHT by 3 units
- \(f(x + 3)\) shifts LEFT by 3 units
- \(f(2x)\) compresses (makes narrower)
- \(f(x/2)\) stretches (makes wider)
Business Applications:
- Seasonal Adjustments: \(D(t) = f(t - 3)\) (peak shifts 3 months later)
- Market Speed Changes: \(L(t) = f(2t)\) (2x faster product lifecycle)
- Time Scaling: Converting quarterly to monthly data
Combining Transformations
Standard Order for: \(g(x) = a \cdot f(b(x - h)) + k\)
- Horizontal shift by h
- Horizontal stretch/compress by factor b
- Vertical stretch/compress by factor a
- Vertical shift by k
Example: Transform \(f(x) = x^2\) to \(g(x) = -2(x - 3)^2 + 5\)
- Shift right 3: \((x - 3)^2\)
- Stretch vertically by 2: \(2(x - 3)^2\)
- Reflect over x-axis: \(-2(x - 3)^2\)
- Shift up 5: \(-2(x - 3)^2 + 5\)
Reading Economic Graphs
Key Features to Identify
Graph Analysis Checklist:
- Intercepts: Starting values, break-even points
- Slope/Rate of change: Marginal values, trends
- Maximum/Minimum: Optimal points, extremes
- Intersections: Equilibrium, equal values
- Shape: Linear, quadratic, exponential patterns
- Domain/Range: Feasible regions, constraints
Business Graph Interpretation
Cost vs Revenue Analysis:
- y-intercept of cost: Fixed costs
- Intersection points: Break-even quantities
- Region between intersections: Profitable zone
- Maximum vertical distance: Optimal production level
- Slope comparisons: Marginal cost vs marginal revenue
Market Analysis:
- Supply/Demand intersection: Market equilibrium
- Shift patterns: Market changes over time
- Area under curves: Total consumer/producer surplus
- Steep vs flat curves: Price sensitivity (elasticity)
Function Composition
Understanding Composition
Composition models sequential processes: \((f \circ g)(x) = f(g(x))\)
Key Points:
- Read as “f composed with g”
- Apply g first, then f to the result
- Output of g becomes input of f
- Order matters: \((f \circ g) \neq (g \circ f)\) usually
- Models multi-step business processes
Steps to Find Composition:
- Calculate \(g(x)\) first
- Substitute result into \(f\)
- Simplify the expression
Common Business Compositions
- Manufacturing: Raw materials → Components → Finished products
- Finance: Local currency → Foreign currency → Investment returns
- Retail: Wholesale → Retail price → After-tax price
- Marketing: Leads → Conversions → Revenue
Domain Considerations
When composing functions, the domain of \((f \circ g)\) is restricted by:
- Domain of g (inner function)
- Values of g(x) must be in domain of f (outer function)
Inverse Functions
What is an Inverse Function?
An inverse function reverses the original function
Definition: If \(f(a) = b\), then \(f^{-1}(b) = a\)
- The inverse “undoes” what the original function does
- Notation: \(f^{-1}(x)\) (read as “f inverse of x”)
- Not the same as \(\frac{1}{f(x)}\) (reciprocal)
Testing for Invertibility
A function has an inverse if and only if it’s one-to-one
Horizontal Line Test:
- Each horizontal line intersects the graph at most once
- Equivalently: each output comes from exactly one input
- For continuous functions: must be always increasing or always decreasing
Finding Inverse Functions
Step-by-Step Process:
- Replace \(f(x)\) with \(y\)
- Swap \(x\) and \(y\)
- Solve for \(y\)
- Replace \(y\) with \(f^{-1}(x)\)
- Verify domain and range
Business Applications of Inverse Functions
Common Business Inverses:
- Demand ↔︎ Price: \(Q = 1000 - 20p\) → \(p = \frac{1000 - Q}{20}\)
- Cost ↔︎ Quantity: \(C = 500 + 25x\) → \(x = \frac{C - 500}{25}\)
- Profit ↔︎ Sales: Find required sales for target profit
- Break-even Analysis: Reverse engineer production requirements
Graphical Properties of Inverses
- Reflection property: Graph of \(f^{-1}\) is reflection of \(f\) over line \(y = x\)
- Domain and range swap: Domain of f = Range of \(f^{-1}\)
- Intersection points: \(f\) and \(f^{-1}\) intersect on line \(y = x\)
Problem Solving
Systematic Problem-Solving Approach
- Identify the context: What business situation is modeled?
- Determine function type: Linear, quadratic, composed, inverse?
- Identify variables: Input (independent) vs output (dependent)
- Check domain restrictions: Mathematical and business constraints
- Write the function: Express relationship algebraically with units
- Apply appropriate techniques: Vertex formula, composition, transformations
- Verify results: Check if outputs make business sense
- Consider practical constraints: Production limits, budget restrictions
Common Pitfalls to Avoid
- Composition order: Remember \((f \circ g) \neq (g \circ f)\)
- Domain issues: Always check for restrictions
- Units confusion: Track currency vs. quantity units carefully
- Inverse vs. reciprocal: \(f^{-1}(x) \neq \frac{1}{f(x)}\)
- Optimization assumptions: Verify that mathematical optimum is practical