
Session 03 - Functions
Mathematics for Master Students
Recap & Your Questions
Session 02 in a Nutshell
- A set is an unordered collection of distinct elements: \(\in\) for elements, \(\subseteq\) for sets
- \(\cup\), \(\cap\), \(\setminus\), \(^c\) mirror or, and, not: De Morgan flips \(\cup\) and \(\cap\)
- Counting a union: \(|A \cup B| = |A| + |B| - |A \cap B|\)
- \(A \times B\) collects ordered pairs: \(\mathbb{R} \times \mathbb{R} = \mathbb{R}^2\) is the plane
- Constraints are sets, and they combine by intersection
- Today: functions map between sets, and their graphs live in \(\mathbb{R}^2\)
Common Issues in the Homework
- Element vs subset: braces build a set: \(\{2\} \subseteq A\) pairs with \(\subseteq\), while \(2 \in A\) pairs with \(\in\); mixing them was the most frequent slip
- Complements reverse inclusion: from \(A \subseteq B\) it follows that \(B^c \subseteq A^c\): writing \(A^c \subseteq B^c\) is the classic inversion error
- Mixed \(\cup\) and \(\cap\): \(A \cap B \cup C\) is ambiguous: grouping changes the set, so always add parentheses
. . .
Which tasks gave you trouble? Bring them up now: we take the time to go through them before we move on to today’s topic.
Warm-Up: One Quick Evaluation
Let \(A = \{1, 2, 3, 4\}\) and \(B = \{3, 4, 5\}\). Compute \(\;(A \cup B) \setminus (A \cap B)\).
. . .
- Inside out: \(A \cup B = \{1, 2, 3, 4, 5\}\) and \(A \cap B = \{3, 4\}\)
- Removing the intersection: \((A \cup B) \setminus (A \cap B) = \{1, 2, 5\}\)
- In words: everything in exactly one of the two sets: “either, but not both”
Today’s Plan
- What is a function?: exactly one output for every input
- Function gallery: linear, quadratic, polynomial, rational, exponential, logarithm
- Domain in practice: which inputs are allowed
- Combining functions: composition and inverses
- Properties: monotone, bounded, convex vs concave
Functions as Mappings
What Is a Function?
A function \(f: A \to B\) is a rule that assigns to each element \(x \in A\) exactly one element \(f(x) \in B\).
- It maps between two sets: the ones from last session
- Think of a machine: input \(x\) goes in, output \(f(x)\) comes out
- “Exactly one” makes it predictable: same input, same output, every time
. . .
“Exactly one” restricts the outputs per input. Two different inputs may share the same output: that is perfectly fine.
Function Notation
\[f: \mathbb{R} \to \mathbb{R}, \quad x \mapsto 2x + 5\]
- \(f\) is the function’s name; \(x\) is the input, also called the argument
- \(f(x)\) is the output: read “\(f\) of \(x\)”; here \(f(x) = 2x + 5\)
- \(x \mapsto f(x)\) reads “\(x\) maps to \(f(x)\)”: note the little bar on the arrow
- \(f: A \to B\) names the two sets: inputs come from \(A\), outputs land in \(B\)
. . .
\(f\) and \(f(x)\) are different things: \(f\) is the rule, \(f(x)\) is a number: the value at \(x\).
Domain, Codomain, Range
For \(f: A \to B\), three sets matter:
- The domain \(A\): all allowed inputs
- The codomain \(B\): where outputs are declared to land
- The range \(f(A) = \{f(x) : x \in A\}\): the outputs that actually occur
- Always \(f(A) \subseteq B\): the range is a subset of the codomain
. . .
Example: \(f: \mathbb{R} \to \mathbb{R}\), \(f(x) = x^2\): codomain \(\mathbb{R}\), but range \([0, \infty)\): no square is negative.
Evaluating a Function
To evaluate, substitute the input everywhere the variable appears, take \(f(x) = x^2 - 2x\):
- \(f(3) = 3^2 - 2 \cdot 3 = 9 - 6 = 3\)
- \(f(0) = 0 - 0 = 0\)
- \(f(-1) = (-1)^2 - 2 \cdot (-1) = 1 + 2 = 3\)
- Note: \(f(3) = f(-1) = 3\): two inputs, same output, allowed
. . .
Put negative inputs in parentheses before squaring: \((-1)^2 = 1\), not \(-1\).
Plugging in Whole Expressions
The input can be an expression: substitute all of it, in parentheses. Again \(f(x) = x^2 - 2x\):
\[f(a + h) = (a + h)^2 - 2(a + h) = a^2 + 2ah + h^2 - 2a - 2h\]
. . .
\(f(a + h) \neq f(a) + f(h)\), check: \(f(1 + 1) = f(2) = 0\), but \(f(1) + f(1) = -1 - 1 = -2\).
. . .
Expressions like \(f(a + h)\) are the raw material of Session 4: “how much does \(f\) change when the input moves by \(h\)?”
The Vertical Line Test
The graph of \(f\) is the set \(\{(x, f(x)) : x \in A\} \subseteq \mathbb{R}^2\): ordered pairs, as in Session 2.
- A curve is the graph of a function \(\Leftrightarrow\) every vertical line hits it at most once
- Why: one input \(x\) must yield exactly one output
- The circle \(x^2 + y^2 = 1\) fails: at \(x = 0\) it contains two points, \(y = 1\) and \(y = -1\)
- Lines, parabolas and exponential curves all pass
Your Turn: Which Graph is a Function?
Which of the two graphs shows \(y\) as a function of \(x\)?
. . .
Only Graph B: A fails the vertical line test: \(x = 1\) gives both \(y = 1\) and \(y = -1\). The kink in B is fine.
Functions in Business
Functions map decisions to outcomes, the core of every quantitative model:
- Cost function \(C(q)\): production quantity \(\to\) total cost
- Demand function \(D(p)\): price \(\to\) units sold
- Production function: input (labor hours) \(\to\) output (units)
- One decision in, one predicted outcome out: that is why models must be functions
. . .
Whenever a spreadsheet column is computed from another column, there is a function behind it.
Function Gallery
Linear Functions
\[f(x) = mx + b\]
- Slope \(m\): the output changes by \(m\) for each unit of input, constant everywhere
- Intercept \(b = f(0)\): the starting level
- From two points on the graph: \(m = \frac{f(x_2) - f(x_1)}{x_2 - x_1}\)
- The workhorse of business models: constant rates
A Linear Cost Function

. . .
\(C(x) = 200 + 5x\): the fixed costs are the intercept, the variable cost per unit is the slope.
Quadratic Functions
\[f(x) = ax^2 + bx + c, \quad a \neq 0\]
- The graph is a parabola: opens upward if \(a > 0\), downward if \(a < 0\)
- The turning point is the vertex, located at \(x = -\frac{b}{2a}\)
- Downward parabolas model trade-offs: revenue rises with price, until demand collapses
A Quadratic Revenue Function

. . .
Demand \(D(p) = 1200 - 20p\) gives revenue \(R(p) = p \cdot D(p) = 1200p - 20p^2\): the vertex \(p = -\frac{1200}{2 \cdot (-20)} = 30\) is the revenue-maximal price.
Polynomials
\[f(x) = a_n x^n + \dots + a_1 x + a_0 \qquad \text{degree } n = \text{highest power}\]

. . .
Degree \(n\) allows up to \(n\) roots and up to \(n - 1\) turning points: far from the origin the leading term \(a_n x^n\) dominates (\(f(x) = x^3 - 3x\) above behaves like \(x^3\)).
. . .
Cubic cost curves \(C(x) = ax^3 + bx^2 + cx + d\) are the classic economics example: costs rise steeply, flatten, then steepen again.
Rational Functions
\[f(x) = \frac{p(x)}{q(x)} \qquad \text{a quotient of two polynomials}\]
- Defined only where \(q(x) \neq 0\): division by zero is the first domain trap
- Near a zero of the denominator, values explode: a vertical asymptote
- For large inputs, the graph can settle toward a horizontal asymptote
The Hyperbola \(f(x) = 1/x\)

. . .
Both axes are asymptotes. Business example: with \(C(x) = 200 + 5x\), the cost per unit is \(\frac{C(x)}{x} = \frac{200}{x} + 5\): it falls toward 5 as volume grows: economies of scale.
Exponential Functions
\[f(x) = a \cdot b^x, \quad b > 0\]
- The variable sits in the exponent: each step multiplies by \(b\)
- \(b > 1\): growth (interest, booming demand); \(0 < b < 1\): decay (depreciation, churn)
- \(a = f(0)\) is the starting value
- The standard base is Euler’s number \(e \approx 2.71828\): Sessions 4–5 show why it is so convenient
Growth and Decay

. . .
Both stay strictly positive and pass through \((0, 1)\): an exponential never reaches zero.
Compound Interest
Deposit \(K_0\) at annual rate \(r\), each year multiplies the balance by \((1 + r)\):
\[K_t = K_0 \cdot \underbrace{(1+r)(1+r) \dots (1+r)}_{t \text{ factors}} = K_0 \cdot (1+r)^t\]
- Session 1’s product idea in action: repeated multiplication becomes a power
- €1000 at \(r = 0.05\): after 15 years \(1000 \cdot 1.05^{15} \approx\) €2079: more than doubled
- As a function of time \(t\), this is exponential growth with base \(b = 1.05\)
Logarithms: Undoing \(e^x\)
The natural logarithm \(\ln x\) answers: which exponent produces \(x\)?
\[y = \ln x \;\, \Leftrightarrow \;\, x = e^y\]
- \(\ln x\) is the mirror image of \(e^x\) across the diagonal
- Defined only for \(x > 0\)
- \(\ln 1 = 0\) and \(\ln e = 1\)

Rules for Logarithms
\[\ln(xy) = \ln x + \ln y \qquad \ln\frac{x}{y} = \ln x - \ln y \qquad \ln(x^k) = k \ln x\]
- Logs turn products into sums and powers into multiples
- The power rule pulls the unknown down from the exponent: that is why logs solve growth questions
- Other bases reduce to \(\ln\): \(\log_b x = \frac{\ln x}{\ln b}\)
. . .
\(\ln(x + y) \neq \ln x + \ln y\): the rules work for products, not sums.
Your Turn: When Has It Doubled?
With continuous growth at rate \(r\), capital follows \(K_t = K_0 \cdot e^{rt}\). When has it doubled?
. . .
\[e^{rt} = 2 \quad \Rightarrow \quad rt = \ln 2 \quad \Rightarrow \quad t = \frac{\ln 2}{r} \approx \frac{0.693}{r}\]
- At \(r = 5\%\): \(t \approx \frac{0.693}{0.05} \approx 13.9\) years: independent of the starting amount
- The same trick handles yearly compounding: \(1.05^t = 2\) gives \(t = \frac{\ln 2}{\ln 1.05} \approx 14.2\) years
Domain in Practice
The Maximal Domain
If no domain is stated, take the maximal domain: the largest set of reals on which the formula is defined.
Three red flags:
- Division by zero: denominators must stay \(\neq 0\)
- Even roots of negatives: under \(\sqrt{\phantom{x}}\) we need \(\geq 0\)
- Logs of non-positives: inside \(\ln\) we need \(> 0\) (strictly!)
. . .
Everything else (polynomials, exponentials) is safe on all of \(\mathbb{R}\).
Finding the Domain: Examples
| Function | Restriction | Maximal domain |
|---|---|---|
| \(\dfrac{1}{x - 3}\) | \(x - 3 \neq 0\) | \(\mathbb{R} \setminus \{3\}\) |
| \(\sqrt{2x + 6}\) | \(2x + 6 \geq 0\) | \([-3, \infty)\) |
| \(\ln(5 - x)\) | \(5 - x > 0\) | \((-\infty, 5)\) |
. . .
The results are intervals. Session 1’s notation pays off: square bracket at \(-3\) (\(\sqrt{0}\) is fine), round bracket at \(5\) (\(\ln 0\) is not).
Your Turn: Find the Domain
What is the maximal domain of \(\;f(x) = \dfrac{\sqrt{x - 2}}{x - 4}\;\)?
. . .
- The root needs \(x - 2 \geq 0\), so \(x \geq 2\)
- The denominator needs \(x - 4 \neq 0\), so \(x \neq 4\)
- Both must hold, intersect the conditions: \([2, 4) \cup (4, \infty)\)
. . .
Collect every restriction first, then combine: one forgotten condition is the typical exam slip.
Domains in Business
Business adds its own restrictions on top of the math:
- Quantities are non-negative: \(q \in [0, \infty)\): no producing \(-50\) pallets
- Capacity caps the allowed quantities: \(q \in [0, 500]\)
- Prices must keep demand meaningful: \(D(p) = 1200 - 20p \geq 0\) forces \(p \in [0, 60]\)
- Model domain = mathematical domain \(\cap\) business constraints: an intersection, as in Session 2
Combining Functions
Composition of Functions
Chaining two functions, apply \(g\) first, then \(f\) to the result:
\[(f \circ g)(x) = f(g(x))\]
- Read from the inside out: the inner function acts first
- Example: \(g(x) = 2x\) and \(f(x) = x + 3\): \(\;(f \circ g)(x) = f(2x) = 2x + 3\)
- But \((g \circ f)(x) = g(x + 3) = 2x + 6\): not the same
- Business reading: multi-stage processes, the output of one stage feeds the next
Order Matters: Voucher and VAT
A webshop applies a €10 voucher \(v(p) = p - 10\) and 19% VAT \(t(p) = 1.19p\) to a net price \(p\):
- Voucher first, then tax: \((t \circ v)(p) = 1.19(p - 10) = 1.19p - 11.90\)
- Tax first, then voucher: \((v \circ t)(p) = 1.19p - 10\)
- The results differ by €1.90 on every order: for the customer, voucher first is cheaper
. . .
Assuming \(f \circ g = g \circ f\): in general, the order cannot be swapped. Always check which function acts first.
Your Turn: Compose in the Right Order
Let \(f(x) = x^2\) and \(g(x) = x + 1\). Compute \(\;(f \circ g)(2)\;\) and \(\;(g \circ f)(2)\).
. . .
- \((f \circ g)(2) = f(g(2)) = f(3) = 9\)
- \((g \circ f)(2) = g(f(2)) = g(4) = 5\)
- Inside out, always, and the order visibly changes the answer
Inverse Functions
The inverse \(f^{-1}\) undoes \(f\):
\[f(a) = b \quad \Leftrightarrow \quad f^{-1}(b) = a\]
- It exists only if \(f\) is one-to-one: every output comes from exactly one input
- Graph check: every horizontal line hits the graph at most once
- \(f(x) = x^2\) on \(\mathbb{R}\) fails: \(f(2) = f(-2) = 4\): which input produced \(4\)?
- Restricting to \([0, \infty)\) repairs it: there \(f^{-1}(x) = \sqrt{x}\)
Finding an Inverse
Write \(y = f(x)\), solve for \(x\), then read the result as a function of the output.
. . .
Demand example: \(q = D(p) = 1200 - 20p\):
\[q = 1200 - 20p \quad \Rightarrow \quad 20p = 1200 - q \quad \Rightarrow \quad p = 60 - \frac{q}{20}\]
. . .
- \(D^{-1}(q) = 60 - \frac{q}{20}\): the price needed to sell exactly \(q\) units
- Check with a pair: \(D(30) = 600\) and \(D^{-1}(600) = 60 - 30 = 30\) ✓
- Domain and range swap: the domain of \(D^{-1}\) is the range of \(D\)
The Notation Trap: \(f^{-1} \neq 1/f\)
- \(f^{-1}(x)\) is the inverse function: the \(-1\) sits on the function name
- The reciprocal of the value is written \((f(x))^{-1} = \frac{1}{f(x)}\)
- Example \(f(x) = 2x\): \(\;f^{-1}(x) = \frac{x}{2}\), but \(\frac{1}{f(x)} = \frac{1}{2x}\): completely different
. . .
Reading \(f^{-1}\) as “one over \(f\)”: for functions, the exponent \(-1\) means undo, not divide.
The Mirror Property

. . .
Swapping input and output reflects the graph across \(y = x\): the point \((3, 4)\) on \(f\) becomes \((4, 3)\) on \(f^{-1}\): exactly how \(\ln x\) mirrored \(e^x\).
Properties
Monotonicity
\(f\) is increasing if \(x_1 < x_2 \Rightarrow f(x_1) \leq f(x_2)\): strictly increasing with \(<\). Decreasing works the same way, flipped.
- Graph reading: strictly increasing = rises left to right, everywhere
- Costs increase in quantity; demand decreases in price
- Strictly monotone \(\Rightarrow\) one-to-one \(\Rightarrow\) invertible: that is why \(e^x\) has an inverse but \(x^2\) on \(\mathbb{R}\) does not
Boundedness
\(f\) is bounded above if some \(M\) satisfies \(f(x) \leq M\) for all \(x\): bounded below works with \(\geq m\).
- \(e^x > 0\): bounded below by \(0\), unbounded above
- A market share lives in \([0, 1]\): bounded on both sides
- \(f(x) = x^2\): bounded below by \(0\), but grows without limit
- Bounds tell you what a model can, and cannot, predict
Convex or Concave?

- Convex: for two graph points, the chord lies above the graph: \(x^2\), \(e^x\)
- Concave: the chord lies below the graph: \(\ln x\), \(\sqrt{x}\): diminishing returns
- Intuition only for now: Sessions 4–5 make it precise and find optima
Closing
Key Takeaways
- A function assigns each input exactly one output: domain, codomain and range are sets
- Know the gallery shapes: linear, quadratic, polynomial, rational, exponential, logarithm
- \(\ln x\) undoes \(e^x\): the power rule \(\ln(x^k) = k \ln x\) solves for exponents
- Maximal domain: no division by zero, no even roots of negatives, no logs of non-positives
- Composition chains processes: order matters; inverses undo, but only one-to-one functions have them
- Monotone, bounded, convex/concave: reading behavior from a graph
Skip order if running long: 1. Mirror Property, 2. Compound Interest (keep one bullet on Growth & Decay), 3. Notation Trap (compress into Inverse Functions callout), 4. compress Functions in Business to its punchline.
Until the Next Session
- Work through the Tasks: problems with worked solutions
- Check yourself with the Self-Test quiz
- Keep the Cheatsheet next to you while practicing
- Note down anything unclear: we start next session with your questions
. . .
When a function confuses you, sketch it: five plotted points reveal more than ten minutes of staring at the formula.
Preview: Session 04: Differentiation
- Central question: how fast does a function change?
- Slopes of curved graphs: the tangent line
- Today’s \(f(a + h)\) becomes the difference quotient
- Marginal cost and marginal revenue: the language of economic decisions
- And \(e^x\) reveals its superpower
. . .
See you there, and bring your questions!
Literature & Further Reading
- These sessions cover the essentials: textbooks offer more depth and practice
- Sydsaeter & Hammond: Essential Mathematics for Economic Analysis
- Jacques: Mathematics for Economics and Business
- Full recommendations on the tutorial’s literature page