
Section 05: Differential Calculus
Test your understanding from Advanced Functions
What happens to \(f(x) = \frac{1}{x-2}\) as \(x\) approaches 2 from the right?
For the rational function \(g(x) = \frac{x^2-4}{x-2}\), what type of discontinuity occurs at \(x = 2\)?
What is the horizontal asymptote of \(f(x) = \frac{3x^2 + 1}{x^2 - 4}\)?
Focus on rational functions and asymptotic behavior
Today we formalize the “limit” concept that explains all this asymptotic behavior!
Limits are the foundation of calculus!
Remember rational functions from Section 04?
Today’s Concept: A limit describes what value a function approaches as the input approaches a specific value.
Notation: \(\lim_{x \to a} f(x) = L\)
“The limit of \(f(x)\) as \(x\) approaches \(a\) is \(L\)”
We write: \(\lim_{x \to 2} f(x) = 4\)


Question: What happens to the price as quantity approaches 100?
Sometimes the approach direction matters!
One-sided limits (like \(\lim_{x \to a^-} f(x)\)) always describe approaching from one direction!
This is how taxes are often handled:

Marginal tax rates, not the effective rate on total income.
For the tax function at €30,000:
A two-sided limit \(\lim_{x \to a} f(x)\) exists if and only if:
Two-sided limits (written simply as \(\lim_{x \to a} f(x)\)) require agreement from both sides. When we say “the limit doesn’t exist,” we typically mean the two-sided limit.
The limit describes approaching behavior, not the actual value at the point.

\(\lim_{x \to 1} f(x) = 2\) (even though \(f(1)\) is undefined)

Left limit ≠ Right limit, so limit doesn’t exist (two-sided!)

\(\lim_{x \to 0^-} f(x) = -\infty\) and \(\lim_{x \to 0^+} f(x) = +\infty\)
Work individually, then compare

Find the following:
Trace the curve from each direction. The y-value you approach is the limit.
A function \(f\) is continuous at \(x = a\) if:
Business Interpretation
Continuity means “no sudden jumps”, important for:

A factory’s cost function changes at 1000 units:
\[C(x) = \begin{cases} 5x + 1000 & \text{if } x < 1000 \\ 3x + 3000 & \text{if } x \geq 1000 \end{cases}\]
Question: Any idea how this might look?

This is continuous! The company planned the transition carefully.

Work individually for 5 minutes
Evaluate the limits from the previous graphs:
For the function below, determine where it is continuous:
\[f(x) = \begin{cases} x^2 + 1 & \text{if } x < 0 \\ 2 & \text{if } x = 0 \\ -x + 3 & \text{if } 0 < x < 3 \\ \frac{6}{x-3} & \text{if } x > 3 \end{cases}\]
Online retailers often use step functions for shipping:

Question: How does this pricing structure influence customer behavior?
Demand exceeds threshold, government releases emergency reserves:

Examples of Discontinuous Price Functions
Policy interventions often create discontinuities. Limits help us analyze prices “just before” and “just after” the threshold.
Business Context: A company’s total cost function is: \[C(x) = 5000 + 20x + 0.001x^2\]
Question: What happens to average cost in the long run?
\[\lim_{x \to \infty} \overline{C}(x) = \lim_{x \to \infty} \left(\frac{5000}{x} + 20 + 0.001x\right)\]
Evaluating limits requires recognizing the type of limit!
Forms like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\) are indeterminate - the form alone doesn’t tell you the answer. The limit could be any number! You must apply techniques (factoring, simplifying) to find the actual value.
Work individually for 8 minutes
Evaluate these limits:
\(\displaystyle\lim_{x \to 3} \frac{x^2 - 9}{x^2 - 5x + 6}\)
\(\displaystyle\lim_{x \to 0} \frac{x^3 - x}{x}\)
\(\displaystyle\lim_{x \to 4} \frac{\sqrt{x} - 2}{x - 4}\)
Work individually for 5 minutes
Evaluate these limits:
\(\displaystyle\lim_{x \to \infty} \frac{3x^2 + 2x}{5x^2 - 1}\)
\(\displaystyle\lim_{x \to \infty} \frac{x + 1}{x^3 - 2}\)
\(\displaystyle\lim_{x \to -\infty} \frac{2x^3}{x^2 + 1}\)
\(\displaystyle\lim_{x \to \infty} \frac{4x^2 - 3x + 1}{2x^2 + x}\)
Work individually for 5 minutes
\(\displaystyle\lim_{x \to 0^+} \frac{1}{x}\)
\(\displaystyle\lim_{x \to 0^-} \frac{1}{x}\)
Does \(\displaystyle\lim_{x \to 0} \frac{1}{x}\) exist? Why or why not?
\(\displaystyle\lim_{x \to 2^-} \frac{x}{x - 2}\) and \(\displaystyle\lim_{x \to 2^+} \frac{x}{x - 2}\)
A manufacturing company has this cost structure:
Work in groups of 3-4
Limits are the foundation of calculus. Next session, we’ll use them to define derivatives!
Work individually, then we compare
For \(f(x) = \frac{x^2 - 9}{x - 3}\): Find \(\lim_{x \to 3} f(x)\) and is \(f\) continuous at \(x = 3\)?
A parking fee function: \[P(t) = \begin{cases} 5 & \text{if } 0 < t \leq 2 \\ 10 & \text{if } 2 < t \leq 4 \\ 20 & \text{if } t > 4 \end{cases}\] Where is \(P(t)\) discontinuous?
Complete Tasks 05-01
See you next time for derivatives!


Session 05-01 - Limits & Continuity Through Graphs | Dr. Nikolai Heinrichs & Dr. Tobias Vlćek | Home