
Section 04: Advanced Functions
Work individually for 5 minutes, then we discuss
Simplify: \(\sqrt[3]{8x^6}\)
What is the domain of \(f(x) = \sqrt{x - 4}\)?
Compare the growth rates: Which grows faster for large \(x\): \(x^3\) or \(x^{3.1}\)?
Focus on power functions and economic applications
Exponential functions will show dramatically different growth behavior!
By the end of this session, you will be able to:
A fundamental shift in perspective
Power Functions: \(f(x) = x^n\) → variable base, fixed exponent
Exponential Functions: \(f(x) = a^x\) → fixed base, variable exponent
Key Difference: Exponentials grow MUCH faster than any polynomial!
The exponential function family
An exponential function has the form: \[f(x) = a \cdot b^x\]
Essential Properties:
Growth vs. Decay patterns

2 minutes individual, 3 minutes pairs, 2 minutes class discussion
Which of these are exponential functions?
Discuss: What makes a function exponential? What are the restrictions?
The most important number in continuous growth
The number \(e ≈ 2.71828...\) is called Euler’s number
\[e = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n\]
What makes e special
The function \(f(x) = e^x\) has unique mathematical properties:
Whenever you see continuous processes in nature, business, or science, \(e\) appears!

Always positive, passes through \((0, 1)\), grows faster as \(x\) increases
Two equivalent ways to model growth
The general exponential growth model can be written as:
Discrete form: \(A(t) = A_0 \cdot b^t\) where \(b > 1\)
Continuous form: \(A(t) = A_0 \cdot e^{kt}\) where \(k > 0\)
These forms are equivalent! Relationship: \(b = e^k\) or \(k = \ln(b)\)
User adoption example
A new app has 1,000 users and grows by 30% monthly.
Discrete model: \(U(t) = 1000 \cdot 1.3^t\) where \(t\) is months
Continuous model: \(U(t) = 1000 \cdot e^{0.2624t}\) (since \(\ln(1.3) ≈ 0.2624\))
Calculations:
Question: Why might the continuous form be more realistic here?
When things decrease exponentially
The exponential decay model:
\(A(t) = A_0 \cdot b^t\) where \(0 < b < 1\)
or: \(A(t) = A_0 \cdot e^{-kt}\) where \(k > 0\)
Question: Any idea where we find this in the real world?
A machine costs €50,000 and depreciates 15% annually.
Model: \(V(t) = 50000 \cdot 0.85^t\)

The power of reinvesting earnings
Simple interest: Only the principal earns interest \[A = P(1 + rt)\]
Compound interest: Interest earns interest \[A = P\left(1 + \frac{r}{n}\right)^{nt}\]
Let’s compound €1 at 100% interest for 1 year (\(P=1, r=1, t=1\)):
\[A = \left(1 + \frac{1}{n}\right)^n\]
This limit gives us Euler’s number \(e\), the foundation of continuous growth!
The mathematical limit of frequent compounding
As compounding becomes instantaneous (\(n \to \infty\)): \[A = P \cdot e^{rt}\]
When to use continuous compounding:
Continuous vs. daily compounding differs by under 0.01% in practice. Compounding frequencies and the Effective Annual Rate follow in Session 08-01.
Key buttons for exponential functions:
| Operation | Keys |
|---|---|
| \(e^x\) | SHIFT + ln |
| \(10^x\) | SHIFT + log |
| \(x^n\) | Use x^ key |
Examples:
Can you identify the errors? Work with your neighbor
Time allocation: 5 minutes to find errors, 5 minutes to discuss
Student work:
“Since \(2^3 = 8\), then \(2^{3x} = 8x\)”
“The function \(f(x) = -2^x\) represents exponential decay”
“If inflation is 3% annually, prices double in \(\frac{100}{3} ≈ 33\) years”
“\((e^2)^3 = e^5\)”
Which wins in the long run?

How base affects growth rate
For exponential growth (\(b > 1\)):
For exponential decay (\(0 < b < 1\)):
Remember: The base determines the rate of growth/decay!
Small changes, dramatic effects
A cent doubled daily for 30 days:
“The greatest shortcoming of the human race is our inability to understand the exponential function.” - Albert Bartlett
Work alone for 5 minutes, then discuss for 5 minutes
Problem 1: Population Growth
A bacteria colony starts with 100 cells and triples every 4 hours.
Work alone for 5 minutes, then discuss for 5 minutes
Problem 2: Investment Comparison
You have €5,000 to invest for 8 years. Compare:
Work alone for 5 minutes, then discuss for 5 minutes
Problem 3: Half-Life & Medication
A medication has a half-life of 6 hours. You take 200mg.
An investment grows from €1,000 to €1,500 in 5 years.
Question: What was the annual growth rate if compounded continuously?
Early pandemic growth (before interventions, approximation):
Model: \(C(t) = 100 \cdot 2^{t/3}\)
Without intervention:
This demonstrates why an early intervention is crucial and “Flattening the curve” was essential as exponential growth is deceptive initially!
Technology advancement
“Computing power doubles every 2 years”
If a processor has 1 billion transistors today:
\[T(t) = 10^9 \cdot 2^{t/2}\]
Predictions:
This exponential growth has driven the smartphone revolution and AI advancement.
Quick doubling time estimation
For growth rate \(r\)% per period: \[\text{Doubling time} ≈ \frac{70}{r}\]
Why 70? It’s a mathematical approximation that works remarkably well for small growth rates!
When exponentials look linear (be careful!)

The logarithm undoes the exponential
\[y = \log_b(x) \quad \Longleftrightarrow \quad b^y = x\]
The logarithm laws themselves were covered in Session 01-05 - today we study the function and its graph.

Find and fix the errors!
Problem: Solve \(\log_2(x) + \log_2(x - 2) = 3\)
Student Solution:
“\(\log_2(x) + \log_2(x - 2) = 3\)
\(\log_2(x + x - 2) = 3\)
\(\log_2(2x - 2) = 3\)
\(2x - 2 = 8\)
\(x = 5\)”
When data spans several orders of magnitude:
Recognition:
When working with power law relationships:
Recognition:
Let’s viusalize both!


On the log-log plot, the straight line confirms a power law relationship. The slope of -0.3 means that doubling production reduces per-unit cost by about 19% (2^(-0.3) ≈ 0.81).
When exponential growth has limits
Real populations can’t grow forever. The logistic model:
\[P(t) = \frac{L}{1 + Ae^{-kt}}\]
Phase 1: Slow Start (Lag Phase)
Phase 2: Rapid Growth (Exponential-like Phase)
Phase 3: Saturation (Plateau Phase)

Where you encounter S-curves in practice
Business & Technology:
Biology & Social:
Unlike pure exponential growth (which is unsustainable), logistic growth is realistic. Every real system has limits!
Work individually for 5 minutes, then discuss
A new social media platform launches with 100 users. The market can support a maximum of 10,000 users (carrying capacity). The growth follows a logistic model where \(t\) is in months.
\[P(t) = \frac{10000}{1 + 99e^{-0.5t}}\]
Exponential vs. Logistic - A visual comparison

Where logarithmic properties are important:
\[\text{pH} = -\log_{10}[\text{H}^+]\]
where \([\text{H}^+]\) is hydrogen ion concentration in mol/L
If orange juice has pH = 3.5:
Question: How much more acidic is orange juice compared to neutral water?
\[3.5 = -\log_{10}[\text{H}^+]\] \[[\text{H}^+] = 10^{-3.5} \approx 3.16 \times 10^{-4} \text{ mol/L}\]
This is 1000 times more acidic than neutral water!
A firm’s profit depends on portfolio size \(x\) (number of clients):
\[P(x) = \frac{80x}{x + 5} - 15\ln(x + 1) + 10\]

Initially, revenue growth outpaces cost growth → profits increase. Eventually, costs catch up and overtake revenue → profits decline!
Today’s essential concepts
5 minutes - Individual work
A new technology startup’s user base is growing exponentially. They started with 1,000 users and now have 4,000 users after 2 years.
Write the exponential growth model \(N(t) = N_0 \cdot b^t\) (find \(b\))
How many users will they have after 5 years?
Is this discrete or continuous growth? What would the continuous model be?
Using the Rule of 70, approximately when will their user base double from the current 4,000?
Session 04-04: Introduction to Trigonometric Functions
Modeling periodic phenomena
Complete Tasks 04-03!
Session 04-03 - Exponential & Logarithmic Functions | Dr. Nikolai Heinrichs & Dr. Tobias Vlćek | Home