
Section 03: Functions as Business Models
Work individually, then we compare together
\[\begin{cases} 2x + 3y = 18 \\ x - y = 1 \end{cases}\]
A company’s costs increase exponentially according to \(C = 1000 \cdot 1.05^t\). After how many years will costs double?
Solve for \(x\): \(\log_2(x+3) + \log_2(x-1) = 3\)
Translate: “The profit equals revenue minus costs, where revenue is 50 euros per unit and costs include a fixed cost of 1000 euros plus 30 euros per unit.”
15 minutes - presentation and discussion
Let’s discuss Mock Exam 02 and the past sections!
This is your chance to have something repeated!
By the end of this session, you can:
A function is a rule that assigns to each input exactly one output
Question: Does this make sense for you?
Symbolic language for modeling
\(f(x) = 2x^2 - 3x + 1\)
Read as: “f of x equals…”
To find \(f(3)\): \(f(3) = 2(3)^2 - 3(3) + 1 = 18 - 9 + 1 = 10\)
Different functions model different business aspects
So far not too difficult, right?
A bakery has:
Question: What is the cost, the revenue and the profit function?
Register a function for repeated use:
Once defined in Tabellen mode, the function is stored for evaluation.
Once f(x) is defined in Tabellen mode:
The calculator generates a table showing function values:
Example: \(f(x) = x^2 - 4x + 3\)
This helps verify zeros and critical points!
Work individually for 5 minutes, then we discuss
Given the functions:
Calculate:
The domain is the set of all possible input values
For \(f(x) = \frac{1}{x-3}\):
For \(g(x) = \sqrt{2x + 6}\):
Production function \(P(x) = 100\sqrt{x}\) where \(x\) is hours of labor:
The range is the set of all possible output values
Range = Output!
For \(f(x) = x^2 + 2\):
For \(g(x) = \frac{1}{x}\) with domain \(x \neq 0\):
Monthly membership revenue \(R(x) = 50x\) where \(x\) is number of members:

For \(g(x) = \sqrt{2x + 6}\): domain = shadow on the \(x\)-axis, range = shadow on the \(y\)-axis.
Each representation offers unique insights
Question: How would you represent this function as table and as graph?
Scenario: Mobile plan costs 20€ base fee plus 0.10€ per minute.
Question: How would you represent this as a function, as a table and as a graph?

A graph only represents a function if every possible vertical line intersects it at most once



One vertical line, one intersection - that is the whole test.
Work alone for 15 minutes
Find the domain of: \(f(x) = \frac{x+2}{x^2-4}\)
Cost function is \(C(x) = 1500 + 25x\) and revenue is \(R(x) = 40x\)
Given the function \(g(x) = 2x + 8\):
10 minutes - exam-style precision
Given \(f(x) = x^2 - 3x\) and the average-cost function \(\bar{C}(x) = \frac{2000 + 25x}{x}\):
Compute and simplify \(f(a + 2)\)
Compute and simplify \(f(2x) - 2f(x)\)
State the domain of \(\bar{C}(x)\) - mathematically and in the business context
Understanding the structure of business costs
\[C(x) = \text{Fixed Costs} + \text{Variable Costs}\]
The relationship between price and quantity
Which of these are functions?
Discuss with your neighbour - input, output, and whether each input has exactly one output:
The last one is subtle: two different quantities can generate the same revenue - so reading “units” from “revenue” may not be unique!
Example: Concert Tickets
The Scenario
A startup produces custom phone cases:
Work in groups of if you like
Work individually and then we compare.
Determine whether each relation represents a function. If it is not a function, explain why using the vertical line test concept.
Each statement below contains one mistake - find it!
“The table \(\{(2, 5), (3, 7), (2, 9)\}\) is a function, because every pair has an output.”
“For \(f(x) = \frac{x+2}{x^2-4}\), I cancel \((x+2)\) first, so the domain is \(\mathbb{R} \setminus \{2\}\).”
“If \(f(x) = x^2\), then \(f(a + b) = f(a) + f(b) = a^2 + b^2\).”
A center has collected data on how membership varies with price.
| Monthly Fee (€) | Number of Members |
|---|---|
| 30 | 400 |
| 40 | 350 |
| 50 | 300 |
| 60 | 250 |
The fitness center has:
Work in groups for 20 minutes
Functions are the backbone of the exam
5 minutes - Individual work
A local gym has fixed costs of 5000€ per month and variable costs of 10€ per member. They charge 40€ per member per month.
03-02: Linear Functions & Economic Applications
Homework Assignment: Complete Tasks 03-01!
Session 03-01 - Function Concepts & Business Modeling | Dr. Nikolai Heinrichs & Dr. Tobias Vlćek | Home